Page 37 - CPVC Fire Sprinkler Products Installation Instructions & Technical Handbook
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TECHNICAL DATA 35
Example: How much expansion can be expected in a 73 m run of DN50 TYCO CPVC Pipe installed in 4°C given a maximum temperature change to 38°C? Additionally, how long should the expansion loop be to compensate for this expansion?
Step 1. Find the temperature change expressed as ∆T. ∆T=38°C–4°C
∆T = 34°C
Step 2. Calculate the change in length expressed as ∆L. ∆L= eL(∆T)
∆L= 0,061x73x34 ∆L = 151,4 mm
Step 3. Find the length of the expansion loop or offset in millimeters
3
L = Length of loop, offset, or charge of direction in millimeters
E = Modulus of elasticity at the maximum temperature (Table L2)
in bar
D = Average outside diameter of pipe (Table D2) in millimeters
S = Working stress at the maximum temperature (Table L2) in bar
∆L = Change in length of pipe due to a change in temperature from Step 2 in millimeters
L =1838 mm
Step 4. Refer to Figure 7.
a-Forlooplength: 1/5L=1⁄5x1838mm=368mm
2⁄5L=2⁄5x1838mm=735mm b-Foroffsetlength:1⁄4L=1⁄4x1838mm=460mm 1⁄2L=1⁄2x1838mm=919mm
c- For change of direction length: L= 1838 mm
